Hi Kaitlyn,
This is like the one we did before; only instead of finding the margin of error, we're looking for he sample size n.
Recall that the formula for margin of error is:
MoE= z*sqrt(p(1-p)/n)
Breaking this down:
z*=z-critical value
p=probability you were given
n=sample size we are looking for
Now, for this problem:
MoE=0.001 (decimal equivalent to 0.1%)
z*=1.96, z-critical value for 95% confidence, worth memorizing if possible
p=0.78
n=n
Substituting:
0.001=1.96*sqrt((0.78*0.22)/n))
Divide both sides by 1.96:
0.00051=sqrt((0.78*0.22)/n))
Square both sides:
0.000512=(0.78*0.22)/n
Multiply both sides by n:
(0.000512*n)=(0.78*0.22)
0.000512n=0.1716
n=0.1716/0.000512
n=659747
This is extremely high because your margin of error--0.1%--is extremely low. I hope this helps.
Joshua L.
10/23/23
Kaitlyn K.
Thank you! Would the answer be .659 then to three decimal points?10/23/23