Amani G.
asked • 10/19/23Calculate the pH of a solution
Calculate the pH of a solution containing 38 g Sr(OH)2 dissolved in 125 mL of solution at 298 K.
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1 Expert Answer
J.R. S. answered • 10/20/23
Tutor
5.0
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Ph.D. University Professor with 10+ years Tutoring Experience
If we assume 38 g of Sr(OH)2 is completely soluble in 125 ml of solution at 298K (which it most probably is not), then we can proceed as follows:
molar mass Sr(OH)2 = 122 g / mol
38 g Sr(OH)2 x 1 mol / 122 g = 0.311 mols
125 ml = 0.125 L
0.311 mols / 0.125 L = 2.49 M Sr(OH)2
Sr(OH)2 ==> Sr2+ + 2OH-
2.49 M.........2.49 M....4.98 M
pOH = -log [OH-] = -log 4.98
pOH = 0.70
pH = 14 - pOH = 14 - 0.70
pH = 13.3
NOTE: Since it is unlikely that 38 g Sr(OH)2 will dissolve in 125 ml, we would need the Ksp or some other additional information to answer this correctly.
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Kayla L.
I have a picture of the step-by-step solution written out. If you message me I can send it to you. It won't let me submit the photo in the answer section.10/20/23