The standard deviation = 2.02
Mean = 19.4
z-value for 9% = 1-0.09 = 0.91 which is equal 1.34 from the z-table
X= 22.1
Followed by the z score formula
Katherine G.
asked 10/18/23The average age of passenger cars is 19.4 years. If the distribution of ages is normal and 9% of the cars are older than 22.1 years find the standard deviation. Round z-value to 2 decimal places.
The standard deviation = 2.02
Mean = 19.4
z-value for 9% = 1-0.09 = 0.91 which is equal 1.34 from the z-table
X= 22.1
Followed by the z score formula
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