Hi Chrislyn,
Remember the formula for area of a rectangle:
a=lw
Area under a uniform probability distribution is always 1, and we have the length 2 from the x-axis, so:
1=2w
w=1/2
Now, to get the probability that x exceeds 1.18, note that the length is 0.72 and probability is an area. Width remains constant, so
l=0.72
w=1/2
A=P=lw=0.72(1/2)
A=P(X>1.18)=0.36
Now, we do the same procedure for x<0.34.
0.34 is a length, width is still constant, so:
A=(0.34)(1/2)
A=P(X<0.34)=0.17
Now, we simply add the probabilities together:
P(X>1.18 or X<0.34)=(0.36+0.17)
P=0.53
I hope this helps.
