J.R. S. answered 10/17/23
Ph.D. University Professor with 10+ years Tutoring Experience
Heat capacity can essentially be defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree.
First, we must assume that both object A and B have the same mass (not stated in the problem). Then, since object A increased the temperature of water by more than did object B, this tells us that it contained more heat per gram. Thus, we conclude that object A had a greater heat capacity.
To look at this numerically, we will calculate the heat capacity of both A and B, assuming 1 g of each, as follows :
Heat gained by water must = heat lost by object A or B
q = mC∆T
q = heat = ?
m = mass of water = 1000 g
C = specific heat of water = 4.184 J/gº
∆T = change in temperature of water = 3.60º for A and 2.75º for B
Heat lost by A:
q = (1000 g)(4.184 J/gº)(3.60º) = 15062 J/gº = heat capacity of A
Heat lost by B:
q = (1000 g)(4.184 J/gº)(2.75º) = 11506 J/gº = heat capacity of B