J.R. S. answered 10/17/23
Ph.D. University Professor with 10+ years Tutoring Experience
PbCO3(s) <==> Pb2+(aq) + CO32-(aq)
Ksp = [Pb2+][CO32-]
molar mass PbCO3 = 267 g / mole
[Pb2+] = [CO32-] = 7.3x10-5 g / L x 1 mol / 267 g = 2.73x10-7 mol / L
Ksp = [2.73x10-7][2.73x10-7]
Ksp = 7.5x10-14