What the approximate boiling point (to the nearest 10 oC) of CCl4 at 500 torr?

Question

What the approximate boiling point (to the nearest 10 ^oC) of CCl₄ at 500 torr?

Answer 1

The following information was gathered from online sources:

Normal boiling point of CCl4 at 760 torr = 350K

∆Hvap CCl4 = 29.82 kJ/mol

Clausius Clapeyron equation:

ln(P2/P1) = -∆Hvap/R (1/T2 - 1/T1)

∆Hvap = 29.82 kJ/mol

R = 8.314 J/Kmol = 0.008314 kJ/Kmol

P1 = 760 torr

T1 = 350K

P2 = 500 torr

T2 = ?

ln(500/760) = -29.82/0.008314 (1/T2 - 1/350)

-0.419 = -3587(1/T2 - 0.002860)

-0.419 = -3587/T2 + 10.26

-10.68 = -3587/T2

T2 = 336K

Converting to ºC

T2 = 336 -273 = 63ºC = 60ºC boiling point of CCl4 @ 500 torr (to the nearest 10º)

NOTE: you may get different answer if you use a different value of ∆Hvap and/or a different boiling point.