J.R. S. answered 10/16/23
Ph.D. University Professor with 10+ years Tutoring Experience
H2O (g) + Cl2O (g) --> 2HOCl (g)
0.004325......0.004325............0............Initial
-x.................-x....................+2x.........Change
0.004325-x.....0.004325-x......2x...........Equilibrium
K = [HOCl]2 / [H2O][Cl2O]
We need to know the K for this reaction at the temperature of the reaction. Then plug in the value for Kc and the equilibrium values for the reactants and products from the ICE table. Solve for x and that will be the equilibrium concentration of H2O