Calculate the volume of 0.200 M NaOH (in mL) needed to completely react with 50.00 mL of 0.0500 M CH3COOH. Do not include units in your typed answer.

Question

Calculate the volume of 0.200 M NaOH (in mL) needed to completely react with 50.00 mL of 0.0500 M CH₃COOH. Do not include units in your typed answer.

Answer 1

NaOH + CH3COOH ==> H2O + CH3COONa ... balanced equation

moles CH3COOH present = 50.00 ml x 1 L / 1000 ml x 0.0500 mol / L = 2.500x10^-3 moles

moles NaOH required = 2.500x10^-3 mol CH3COOH x 1 mol NaOH / mol CH3COOH = 2.500x10^-3 mol

volume NaOH required = 2.500x10^-3 mol x 1 L / 0.200 mol = 0.0125 L = 12.5 ml = 12.5 (no units)