A ​14-foot ladder is placed against a vertical wall of a​ building, with the bottom of the ladder standing on level ground 7 feet from the base of the building.

Question

How high up the wall does the ladder​ reach?

Answer 1

614 ft ladder,7 ft from base

it's 7sqrt3 =about 7(1.732)= 12.124 ft high on the wall

= 14sin60 =14(sqr3/2)

or use the Pythagorean Theorem

a^2 = 14^2 - 7^2= 196-49=147

a=sqr147=sqr(49(3))=7sqr3= about 12 feet high

or Law of Cosines

14^2 = 7^2 + a^2 -2(7)aCos90 = 49+a^2 - 0 = 49 +a^2

a^2=147

a = a little over 12. 12 squared = 144

or Law of Sines

a/Sin60 = 14/Sin90 = 14/1= 14

a = 14sin60= 14(sqr3)/2= 7sqr3

Answer 2

h² = 14² - 7²

Can you calculate h and answer?