Given the following reaction below, how many grams of H2O (MM = 18.02 g/mol) can be formed from 7.234 grams of C12H26 (MM = 170.34 g/mol)? 2 C12H26 (g) + 37 O2 (g) → 24 CO2 (g) + 26 H2O (g)

Answer 1

2C₁₂H₂₆(g) + 37O₂(g) ==> 24CO2(g) + 26H₂O(g) .. balanced equation

Use the stoichiometry of the balanced equation along with dimensional analysis as follows:

7.234 g C₁₂H₂₆ x 1 mol C₁₂H₂₆ / 170.34 g x 26 mol H₂O / 2 mol C₁₂H₂₆ x 18.02 g H₂O / mol = 9.949 g H₂O