0.2192 g of calcium hydroxide, Ca(OH)2, in 43.75 mL of solution

Answer 1

You have provided us with some information, but there is no question being asked. Maybe you are asking for the molarity of this solution? If so, we can proceed as follows:

molarity (M) = moles of Ca(OH)2 per liter of solution

molarity Ca(OH)2 = 74.09 g / mole

moles Ca(OH)2 used = 0.2192 g x 1 mol / 74.09 g = 2.959x10^-3 moles

volume of solution = 43.75 ml x 1 L / 1000 ml = 0.04375 L

Molarity (M) of solution = 2.959x10^-3 moles / 0.04375 L = 0.06762 M (4 sig. figs.)