William C. answered 10/03/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
If sin(2x) = 5/13 then cos(2x) = 12/13
[Note that we get cos(2x) either by drawing the 5-12-13 right triangle
or from the identity cos2(2x) = 1 – sin2(2x) = 1 – 25/169 = 144/169]
We know that our angle is in the first quadrant, so all six trig functions will have positive values.
We can use half-angle formulas to find sin(x) and cos(x)
sin(x) = √[(1 – cos(2x))/2] = √[(1 – 12/13)/2] = √[(1/13)/2] = 1/√26
cos(x) = √[(1 + cos(2x))/2] = √[(1 + 12/13)/2] = √[(25/13)/2] = 5/√26
Check: sin2(x) + cos2(x) = 1/26 + 25/26 = 1
tan(x) = sin(x)/cos(x) = (1/√26)/(5/√26) = 1/5
csc(x) = 1/sin(x) = √26
sec(x) = 1/cos(x) = (√26)/5
cot(x) = 1/tan(x) = 5