y = –3x –2
Compare with linear equation y=mx+b
m=-3 and b=-2
Method 1: Parallel line will have same slope m=-3 so equation will be y=-3x+b
As we know parallel line y=-3x+b passes through the point (-4,-5), we can find the value of b.
y=-3x+b
-5=-3(-4)+b
-5=12+b
-17=b
Parallel line equation is y=-3x-17
Method 2: Parallel line will have same slope m=-3 and passes through the point (-4,-5), we can use point equation of a line : point slope form.
m=-3, x1=-4 , y1=-5
y-y1=m(x-x1)
y-(-5)=-3(x-(-4))
y+5=-3(x+4)
y+5=-3x-12
y=-3x-17
Parallel line equation is in slope intercept form y=-3x-17