J.R. S. answered 10/02/23
Ph.D. University Professor with 10+ years Tutoring Experience
q = C∆T
q = heat = ?
C = calorimeter constant (heat capacity) = 45.80 kJ/º (note: K or C temperature scale doesn't matter)
∆T = change in temperature = 2.88º
q = (45.80 kJ/º)(2.88º) = 131.90 kJ
On a per gram basis, this is 131.90 kJ / 6.60 g = 19.98 kJ
The question asks for the answer in Calories (nutritional calories) so we convert kJ to Calories as follows:
19.98 kJ x 1 Cal / 4.184 kJ = 4.78 Cal/g (3 sig.figs.)