J.R. S. answered 09/28/23
Ph.D. University Professor with 10+ years Tutoring Experience
Adding KCN to a solution of HCN will create a buffer solution since it will then contain a weak acid (HCN) and the salt (conjugate base) of that acid (KCN). For a buffer of this nature, we can use the Henderson Hasselbalch equation to find the pH.
pH = pKa + log [salt] / [acid]
pKa = -log Ka = -log 4.9x10-10 = 9.31
8.86 = 9.31 + log [x M KCN] / 0.90 M HCN]
8.86 = 9.31 + log x/0.90
-0.45 = log x/0.90
0.355 = x / 0.90
x = 0.320 M KCN
Molar mass of KCN = 65.1 g / mol
125 ml = 0.125 L x 0.320 mol / L KCN = 0.040 mols KCN needed
0.040 mols KCN x 65.1 g / mol = 2.6 g KCN need to be added