William C. answered 09/27/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
x = vt so t = x/v
Let
x be the distance of side of the block (in mi)
t be the time (in hr) it takes to travel that side
and v be the speed in mi/hr
To walk the first side at a speed of 1 mi/hr it takes (x mi)(1 mi/hr) = t hrs
To walk the second side at a speed of 2 mi/hr it takes (x mi)(2 mi/hr) = ½t hrs
To walk the second side at a speed of 2 mi/hr it takes (x mi)(3 mi/hr) = ⅓t hrs
To walk the second side at a speed of 2 mi/hr it takes (x mi)(4 mi/hr) = ¼t hrs
The total time it takes to walk the whole block is (1 + ½ + ⅓ + ¼)t =
(12/12 + 6/12 + 4/12 + 3/12)t = (25/12)t hrs
The total distance walked is 4x mi
v = x/t = 1 mi/hr for the first side
vavg = (4x)/[(25/12)t] = 4/(25/12) × x/t = 4/(25/12) = 48/25
is the average speed for the whole block.
Answer
Billy's average speed is 48/25 mi/hr
Note
Expressed as a decimal this is 1.92 mi/hr
which is less than the number you arrive at
by taking the average of the four speeds.
This incorrect number is (1 + 2 + 3 + 4)/4 = 2.5 mi/hr