J.R. S. answered 09/27/23
Ph.D. University Professor with 10+ years Tutoring Experience
Assuming both the KIO3 and H2SO4 go into the same solution (solution A), you would proceed as follows:
molar mass KIO3 = 214 g / mol
50.00 ml = 0.05000 L
0.200 mol KIO3 / L x 0.05000 L x 214 g / mol = 2.14 g KIO3 needed
For H2SO4: (x ml)(0.625 M) = (50 ml)(0.0800 M)
x = 6.4 mls of 0.625 M H2SO4 needed
Weigh out 2.14 g KIO3. Place in a 50.00 ml volumetric flask. Dissolve in sufficient distilled water. Add 6.40 mls of 0.625 M H2SO4, and dilute solution to a final volume of 50.00 mls.