Calculate the solubility of nitrogen in water

Question

The solubility of nitrogen in water is 8.21×10^-4 mol/L at 0∘C when the nitrogen pressure above the water is 0.790 atm. Calculate the solubility of nitrogen in water when the nitrogen pressure above the water is 1.10 atm at 0∘C.

Answer 1

Henry's Law.

C = H x P

C = concentration = 8.21x10^-4 mol / L

H = Henry's constant = ?

P = Pressure = 0.790 atm

Solving for H, we have ...

H = C/P = 8.21x10^-4 mol / L / 0.790 atm

H = 10.4 M/atm

Using this value of Henry's constant, we can now find the solubility @ 0ºC of N2 when the pressure is 1.10 atm.

C = H x P

C = ?

H = 10.4 M/atm

P = 1.10 atm

Solving for C, we have ...

C = 10.4 M/atm x 1.10 atm

C = 11.4 M = 11.4 mol / L