J.R. S. answered 09/09/23
Ph.D. University Professor with 10+ years Tutoring Experience
In the buffer system of NaHCO3 + Na2CO3, HCO3- (NaHCO3) acts as the weak acid, CO32- (Na2CO3) acts as the conjugate base.
When acid (HCl) is added, it will react with the conjugate base Na2CO3 to produce the weak acid NaHCO3.
Na2CO3(aq) + HCl(aq) ==> NaCl(aq) + NaHCO3(aq) ... molecular equation
2Na+(aq) + CO32-(aq) + H+(aq) + Cl-(aq) ==> 2Na+(aq) + Cl-(aq) + HCO3-(aq) ... total ionic equation
CO32-(aq) + H+(aq) ==> HCO3-(aq) ... net ionic equation
When base (NaOH) is added, it will react with the acid NaHCO3 to produce the conjugate base Na2CO3.
NaHCO3(aq)+ NaOH (aq) ==> H2O(l) + Na2CO3(aq) ... molecular equation
Na+(aq) + HCO3-(aq) + Na+(aq) + OH-(aq) ==> H2O(l) + 2Na+(aq) + CO32-(aq) ... total ionic equation
HCO3-(aq) + OH-(aq) ==> H2O(l) + CO32-(aq) ... net ionic equation