Please how do you solve this?

Question

Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers so that ∠A₁ is smaller than ∠A₂.)

b = 45,    c = 44,    ∠C = 36°

∠A1 =	°		∠A2 =	°
∠B1 =	°		∠B2 =	°
a1 =			a2 =

Answer 1

C=36

c=44

b=45

sinB/b = sinC/c

sinB = bsinC/c = 45sin36/44

B = arcsin(45sin36/44)= 36.95 or 180-36.95 = 143.05 degrees

B=37 degrees or 143

A=180-37-36 = 107 degrees or 180-143-36 = 1 degree

a/sinA = c/sinC =b/sinB

a = csinA/sinC = 45sin107/sin36

a= 71.6

or

a= 45sin1/sin36 = 1.3

2 possible triangles

an acute triangle is 1, 36, 143 degrees with sides 1.3, 44, 45

an obtuse triangle is 36,37, 107 degrees with sides 44,45, 71.6

largest angle is opposite the largest side

smallest angle is opposite the smallest side

b-c<a<b+c

1<a<99

a is less than the sum of the other two sides

and a is greater than the difference of the other two sides

in general there will be either 0, 1 or 2 possible triangles