J.R. S. answered 09/01/23
Ph.D. University Professor with 10+ years Tutoring Experience
Trial 2 vs. trial 1: [N2] is constant; [H2] increases 4.42x. Rate increases 19.5x. 2nd order in H2.
Trial 1 vs. trial 3: [H2] is constant; [N2] increases 2.1x. Rate increases 4.5x. 2nd order in N2.
Rate law:
Rate = k[N2]2[H2]2
Using values in trial 1, compute the value of k:
25.0 M/s = k[1.87 M]2 [1.78 M]2
25.0 M/s = 11.1 M4k
k = 2.3 M-3s-1