J.R. S. answered 09/01/23
Ph.D. University Professor with 10+ years Tutoring Experience
Comparing trial 1 to trial 2, [N2] is constant and [H2] increases by 4.76x. The rate increases by 22.7x. This tells us the reaction is 2nd order in H2.
Comparing trial 1 to trial 3, [H2] is constant and [N2] increases by 3.33x. The rate increases by 3.33x. This tells us the reaction is 1st order in [N2].
Now we can write the rate law as ...
Rate = k[N2][H2]2
Use any trial and plug in the values and solve for k. We will use trial 1...
0.484 M/s = k(1.36 M)(0.913 M)2
0.484 M/s = 1.134 M3k
k = 0.43 M-2s-1