Chemistry help!

Question

I think its the program but I know the answer is 87.5. I was wondering If anyone could help me set it up by chance.

Question: What volume of 0.100 M HCl solution is needed to neutralize 25.0 mL of 0.350 M NaOH solution?

And it wants it where you cancel out the units (Like doing stoichiometry and not v1v2= stuff)

Answer 1

The method of canceling units, which is requested, is generally referred to as "unit factor" or "dimensional analysis. But first, we must write a correctly balanced equation for the reaction taking place:

HCl + NaOH ==> NaCl + H2O

Then we can use dimensional analysis to find the volume of 0.100 M HCl needed, as follows:

25.0 ml NaOH x 1 L /1000 ml x 0.350 mol/L x 1 mol HCl / mol NaOH x 1 L / 0.100 mol HCl = 0.0875 L

Notice that ml NaOH cancel, mols NaOH cancel, mol HCl cancel, leaving L (liters) of HCl.

If you want to convert this to mls of HCl, then 0.0875 L HCl x 1000 mls / L = 87.5 mls HCl