what is the equilibrium constant for the following reaction

Question

At a certain temperature, the equilibrium constant K

 for the following reaction is ×5.0810−9

H₂(g)+Cl₂(g)  2HCl(g)

Use this information to answer the following question. 

what is the equilibrium constant for the following reaction? Round your answer to 3 significant figures.

2HCI(g)  H₂(g)+CI(g) K =

Answer 1

H₂(g) + Cl₂(g) <==> 2HCl(g) .. K = 5.08x10^-9

2HCl(g) <==> H₂(g) + Cl₂(g) .. K = 1 / 5.08x10^-9 = 1.97x10⁸

The equilibrium constant for the reverse reaction (K')will be the reciprocal of the original K (1/K)