Find a point E on C D such that the ratio of C E to C D is one-fourth.

Question

c is -9 and d is 7.

Answer 1

here is how to create formula

(1/4)point=(1/4)(d-c)+c

saying the 1/4 point between c and d is (1/4) of the distance from c to to d, and add to c

(1/4)point=((d-c)/4)+(4c)/4

(1/4)point=(3c+d)/4

c=-9, d=7 (1/4)point=-5

using same procedure

(1/2) point=(c+d)/2

(1/3)point=(2c+d)/3

(1/5)point=(4c+d)/5

it is not intuitive that for something that begins as a subtraction becomes in

the formula addition.

for (2/7)point_cd=(2/7)(d-c)+(7c)/c

=(5c+2d)/7

Answer 2

CD is on a number line

>----C------------------D-------->

Where C is a point and D is a point.

>----C----E------------D-------->

Where CE is (1/4) of CD.

>----C------------------D-------->

-9. 7

The length of CD is 16, or [-9+7]

E=(1/4)16 = 4

(1/4) of CD is 4.

Point E=4