A bookkeeper earned $12,200 his first year on a job and received a raise of $675 each year thereafter. What did he earn during his 12th year on the job?

Answer 1

an = 12200 +675(n-1)

a12 = 12,200 +675(12-1)

= 12200 + 7425

= $19,625 in the 12th year

it's an arithmetic sequence

with common difference = 675

1st term = 12,200

nth term = an = a1+d(n-1)