Determine the solubility (M) of unknown gas A in soda water at 25°C if the pressure of A is 9,500 torr. The Henry's law constant for carbon dioxide in water at this temperature is 2.5 × 10-2 M/atm.

Answer 1

Henry's law states that at a constant temperature, the solubility of a gas in a liquid is proportional to the partial pressure of the gas.

C = kP

C = concentration = ?

k = 2.5x10^-2 M/atm

P = 9500 torr

Change 9500 torr to atm: 9500 torr x 1 atm / 760 torr = 12.5 atm

Solve for C: C = 2.5x10^-2 M/atm x 12.5 atm = 0.31 M