What is the entropy change when 1.40 moles of CCl₂F₂ condenses at 25.0 °C? [∆H(vap) = 17.2 kJ/mol at 25.0 °C]

Answer 1

∆S = ∆Hvap / T

∆S = ?

∆Hvap = 17.2 kJ / mol

T = 25ºC + 273 = 298K

∆S = 17.2 kJ / mol x 1.40 mol = 24.08 kJ / 298K = 0.0808 kJ/K = 80.8 J/K