Determine ∆S for the phase change of 1.38 moles of water from solid to liquid at 0 °C. (∆H = 6.01 kJ/mol)

Answer 1

The entropy change for a phase change at constant pressure is given by ΔS = q/T

∆S = ?

q = ∆Hfusion = 602 kJ/mol

T = 273K

∆S = 6.01 kJ / mol / 273 K x 1.38 mols = 0.0304 kJ/K = 30.4 J/K