J.R. S. answered 07/25/23
Ph.D. University Professor with 10+ years Tutoring Experience
C2H4(g) + 3O2(g) --> 2CO2(g) + 2H2O(l) .. -1401kJ/mole
2CO2(g) + H2O (l) --> C2H6(g) + 7/2 O2(g) .. +1550 kJ/mole
H2(g) + 1/2 O2(g) --> H2O(l) .. -286 kJ/mole
--------------------------------------------------------------------
C2H4(g) + 3 O2(g) + 2CO2(g) + H2O(l) + H2(g) + 1/2 O2(g) --> 2CO2(g) + C2H6(g) + 7/2 O2(g) + H2O(l)
C2H4(gO + H2(g) --> C2H6(g) .. -140 +1550 -286 = 1124 kJ/mole