J.R. S. answered 07/21/23
Ph.D. University Professor with 10+ years Tutoring Experience
Not sure if you are asking to calculate the molarity or the molality (but not morality).
If we have 1 liter (1000 ml) of solution, then we have ...
1000 mls x 1.84 g / ml = 1840 g of solution
mass of H2SO4 = 1840 g x 95% = 1748 g H2SO4
moles H2SO4 = 1748 g x 1 mole / 98 g = 17.8 moles H2SO4
Molarity (M) = 17.8 moles / 1 L = 17.8 M
If you want the molality (m), subtract the mass of H2SO4 (1748 g) from the total mass (1840 g) to get mass of solvent. Convert that mass to kilograms. Finally, divide moles H2SO4 (17.8) by kg of solvent. Recall that molality (m) is moles of solute / kg of solvent.