write the equation of a line perpendicular to y=1/3x-9 that passes through the point (-6,10)

Answer 1

The slope of the given line is 1/3, so a line perpendicular to that will have a slope of -3 (the negative reciprocal of 1/3)

Since we have the slope of the line and a point it goes through, we can use point-slope form to write the equation.

So it’s y-10=-3(x+6)

Answer 2

-3=(y+6)/(x-10)