what % of the area under the curve of the standard normal distribution is outside the interval z= [-0.86,0.86] (or beyond 0.86 standard deviations of the mean).

Question

id specifically like to know how to put this into a calculator so I'm able to learn how to get the answer. Thank you!

Answer 1

type in 2nd vars (which is distr)

On the menu, pick Pick 2: Normalcdf

set lower bound to -.86 and upper bound to .86. The default distribution is the standard normal with mu = 0 and sigma = 1. You can solve directly my changing these given x values, mu, and sigma for an applied problem.

Hit paste, hit enter again and you will have P(-.86<z<.86)

The area you are looking for is 1-P (The area outside of these values - the total area is 1). This will be a decimal value (x 100 for percent)

Please consider a tutor. Take care. (I get 38.98%)