Calculate the mass of(NH2)2CO that could theoretically be formed by this reaction.

Answer 1

2NH3(g) + CO2(g) ==> (NH2)2CO(aq) + H2O(l).

Whenever given amounts of both reactants, you must first find the limiting reactant:

One way is to divide mols of each reactant by the corresponding coefficient and whichever value is less is the limiting reactant.

For NH3: 637.2 g NH3 x 1 mol NH3 / 17 g = 37.48 mols NH3 (÷2->18.74)

For CO2: 1142 g CO2 x 1 mol CO2 / 44 g = 25.95 mols CO2 (÷1->25.95)

Since 18.74 is less than 25.95, NH3 is LIMITING

Now use moles of NH3 (37.48 mols) to find theoretical yield of (NH2)2CO:

37.48 mols NH3 x 1 mol (NH2)2CO / 2 mols NH3 = 18.74 mols (NH2)2CO

molar mass (NH2)2CO = 60.06 g/mol

grams (NH2)2CO formed = 18.74 mols (NH2)2CO x 60.06 g / mol = 1126 g (NH2)2CO

Answer 2

Hi there,

I need more information to answer this question. What is the reaction that you are given?

Thanks.