Akansha M. answered 06/27/23
UCLA Psychobiology Student and Lover of Learning
Hi,
Here we use the Binomial Probability Function:
P(X = x) = n! / ((n-x)! x!)(p)x(q)n-x
where X is is our random variable which represents the number of students graduating
n = 10 the sample size
p = .909 the probability of success (students graduate)
q = .091 the probability of failure
a) P(X ≥ 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 10! / (10-6)! 6!(.909)6(.091)10-6+ 10! / (10-7)! 7!(.909)7(.091)10-7+10! (10-8)! 8!(.909)8(.091)10-8...10! (10-10)! 10!(.909)10(.091)10-10
I'll let you attempt this on your own first, but let me know if you have any questions and I would be happy to go into more detail!
b) To find the probability of an exact number of students graduating, you can use the same formula.
P(X = 7) = 7! / (10-7)! 7!(.909)7(.091)10-7
c) For this question, you are being asked to interpret your answer to the previous question. You should get a very small value, which tells you that it is unusual for exactly 7 students to graduate.
d) This question is similar to part a, but this time you are being asked to find the probability of at most 7 graduated. The phrase "at most" implies that you should solve for P(X ≤ 7) using the same method that you did in part a. P(X ≤ 7) = P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3)+P(X = 2) +P(X = 1)
e) For this question, you are being asked to interpret your answer to the previous question. If you get a very small value, this tells you that it is unusual for this event to occur. On the other hand, if you get a very large value, this tells you that the event is not unusual.
Let me know if you have any questions! Hope this helped!