Recall the formula for a Poisson probability distribution is P(X=x) = (e-λλx)/x! where λ is the mean number of occurrences in the given interval and x is the desired number of outcomes in the given interval.
Here, λ=1.2 and x=3, so P(X=x) = (e-1.2•1.23)/3! ≈ 0.087
Thus, the probability that on a given practice the roper will miss exactly 3 times this practice is 0.087
Hope this helped!