J.R. S. answered 05/29/23
Ph.D. University Professor with 10+ years Tutoring Experience
Answer: (A) Li+ is larger than Be2+
Explanation:
We begin with the periodic trend that atomic radius increases within a period going from right to left across the table, and it increases within a group going down the table. We next apply the fact that the cation is smaller than the neutral element since it has LOST an electron from the outer shell.
Comparing Li to Be, Li is to the left of Be so is larger, and Li+ and Be2+ are isoelectronic
Comparing L+ to Li, Li+ is smaller since it lost an electron
Comparing Li+ to Na+, Li is above Na so it is smaller
Comparing Be to Mg, Be is above Mg so it is smaller