µ=145
σ=13
n=49
Since n is large, according to the central limit theorem, the sampling distribution of X is approximately normal. If you are using a TI84
P(144 < X < 148) = normalcdf(144,148,145,13/sqrt(49)) = 0.6518
or
P(144 < X < 148) = P((144-145)/(13/sqrt(49) < Z < (148-145)/(13/sqrt(49))
P(-0.5385 < Z < 1.6154)
this can also be solved with a TI84
=normalcdf(-0.5385, 1.6154,0,1)=0.6518
or with tables.
If you want you can let me know what method you use in your class and I can explain it that way.
Let me know if you have any questions.
Dian