Given: triangle ACE, B and D are themidpoints of line AC and line EC, respectively. Show a solution. 1. If AE = 4x + 8 and BD = 18, then x = ___________.

Question

2. If m∠A + m∠E = 108°,m∠CBD = (5x + 11) ° andm∠CDB = (6x - 2) °,then m∠A = ___________.

3. If AB = 2x + 5, BC = 3x - 6 andBD = 4x - 12, then AE = _________.

4. If AE = 12x + 2 and BD = 3x + 10, then BD = __________.

5. If ∆CBD is isosceles, m∠C = 100°, CB = 8x + 7 and DE = 7x +8,then AC = __________.

Answer 1

I hope you find this helpful, and please comment or reach out for any further tutor support. Peace! :)

~ Happy Learning ~

Answer 2

Hi! The Midsegment Theorem states that the line segment that joins the midpoints of two sides of a triangle is parallel to, and half the length of the third side.

So if BD = 18, that means AE = 36.

4x + 8 = 36.

Subtract 8, then divide by 4. x = 7.