Ammonia (NH3) clouds are present around some planets. Calculate the number of moles of ammonia produced by the reaction of 5.4 g of hydrogen with an excess of nitrogen. N2 + 3 H2 ->2 NH3

Answer 1

N₂(g) + 3H₂(g) ==> 2NH₃(g) .. balanced equation

How many moles of H2 do we have?

5.4 g H₂ x 1 mol H₂ / 2.0 g = 2.7 mols of H₂

Since there is excess N₂, we need not concern ourselves with a limiting reactant, as it will be H₂.

Next, we use the mole ratio of NH₃ : H₂ in the balanced equation (2 : 3) and dimensional analysis to find our answer:

2.7 mols H₂ x 2 mols NH₃ / 3 mols H₂ = 1.8 mols NH₃