If 126.0 grams of methane gas are recovered in the lab, what is the percent yield of methane gas?

Answer 1

Ryleigh... I assume this is based on the previous question you posted. I answered that and found the theoretical yield of CH4 to be 156.9 g.

The % yield is the actual yield / theoretical yield (x100%)

% yield = 126.0 g / 156.9 g (x100%) = 80.31%

Answer 2

To calculate the percent yield of methane gas, you would need to compare the amount of methane gas recovered in the lab (the actual yield) to the theoretical yield, which is the amount of methane gas that would be obtained if the reaction proceeded perfectly.

To determine the theoretical yield, you would need to know the reaction involved and the stoichiometry of the reaction. Assuming the reaction is the complete combustion of methane.

Answer 3

First you have to tell us the chemical reaction happening here, and then a number for at least one of the reactants you started with.

Once you know those two things, you can use stoichiometry to figure out how much methane you were SUPPOSED to get out of the reaction.

Percent yield is all about the difference between how much stuff you were supposed to get, versus how much of that stuff you ACTUALLY got. So for example, if I only got 126g of CH4, but was actually supposed to get 252g, then that means I only got half out, or I had a 50% yield.

If that doesn't answer your question please comment below. Good luck!