Find the value of x and y for which the quadrilateral is a parallelogram. Show your solution and explain. (Need answer today pls)

Question

Answer 1

The diagonals of a parallelogram cut each other in half...or in "mathy" terms, they bisect each other.

So, you can set the two halves of each diagonal equal to each other: x + y = 10, and x - y = 8.

What I would recommend, is get x by itself in the 2nd equation by adding y to both sides, so you end up with: x = 8 + y.

You can then substitute "8 + y" in for x in the other equation. So in the 1st equation, you now have 8 + y + y = 10.

Combine like terms: 8 + 2y = 10.

Subtract 8: 2y = 2

Divide by 2: y = 1.

You can then plug y = 1 into either original equation to find the value of x.

So you either have x - 1 = 8, or x + 1 = 10. You will end up with x = 9.

Answer 2

The diagonals of a parallelogram bisect each other!