In an endothermic reaction at equilibrium, if you decrease the temperature, what will happen?

Question

In an endothermic reaction at equilibrium, if you decrease the temperature, what will happen? 

:

	the amount of reactant and product will stay the same
	more product will be formed
	more reactant will be formed
	the reaction will go to completion and there will be no reactants left

(Thank you so much in advance)!!! I don't understand this! And I appreciate the help

Answer 1

I think you asked this same question a day ago, and I provided an answer. If you don't understand the answer I provided, please tell us why and maybe I can make it clearer. Otherwise, I'm bound to provide the same or a similar answer.

Here's the answer I gave the other day:

This question deals with understanding Le Chatelier's principle. This states that a system at equilibrium will act to reverse any perturbation placed on that system, i.e. it will change to counteract the change that has been made to it.

An endothermic reaction is one in which heat is added to it, so heat can be viewed as a REACTANT. Thus we can write the reaction as A + B + HEAT ==> C + D

Decreasing the temperature is the same as removing heat. Thus, you are removing a reactant.

This will result in a shift to the left, toward the reactant side.

This will result in formation of more reactant = Answer C

If you don't understand this explanation, please leave a comment stating why you don't understand.