J.R. S. answered 05/12/23
Ph.D. University Professor with 10+ years Tutoring Experience
Simply use V1M1 = V2M2
V1 = initial volume; M1 = initial molarity; V2 = final volume: M2 = final molarity
(x ml)(4.2 M) = (500 ml)(1.5 M)
x = 179 mls
Benjamin S.
asked 05/11/23What volume of 4.2 M Ca(OH)2 is needed to make 500mL of 1.5M solution
J.R. S. answered 05/12/23
Ph.D. University Professor with 10+ years Tutoring Experience
Simply use V1M1 = V2M2
V1 = initial volume; M1 = initial molarity; V2 = final volume: M2 = final molarity
(x ml)(4.2 M) = (500 ml)(1.5 M)
x = 179 mls
William W. answered 05/11/23
Math and science made easy - learn from a retired engineer
A 1.5 M solution means it has 1.5 moles/liter. Since there is 500 mL, or 1/2 liter, then there is 0.75 moles of Ca(OH)2 in the final solution.
Let "x" represent the volume (in liters) of the initial 4.2 M solution
Since you are starting with a 4.2 M solution, or 4.2 moles/liter, then the number of moles is 4.2x and since you want that number of moles to be 0.75 then:
4.2x = 0.75
x = 0.75/4.2 = 0.179 liters or 179 mL
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