Given P (A) = 0.65 P(A)=0.65, P (B) = 0.42 P(B)=0.42 and P ( A∣B ) = 0.8 P(A∣B)=0.8, find the value of P ( A and P) P(A and B), rounding to the nearest thousandth, if necessary.

Answer 1

.8 x .42 = .336 = P(A&B) = 33.600% = about 1/3 chance

it may help to draw a Venn diagram

or use Bayes Theorem