MOE = z(s/√n)
50 = 1.44(289/√n)
50 = 416.16/√n
√n = 416.16/50
√n = 8.3232
n = 69.27565824 <-- round up to n=70
Therefore, you should sample 70 students to get a margin of error of 50.
Hope this helped!
Pam T.
asked 05/08/23The SAT scores are distributed with a mean of 1500 any standard deviation of 289. You’re interested in estimating the average SAT score a First your students at your college if you would like to limit the margin of error of your confidence interval to 50 points with an 85% confidence how many students should you sample round up to a whole number of students
MOE = z(s/√n)
50 = 1.44(289/√n)
50 = 416.16/√n
√n = 416.16/50
√n = 8.3232
n = 69.27565824 <-- round up to n=70
Therefore, you should sample 70 students to get a margin of error of 50.
Hope this helped!
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