At what temperature (K) will a 3.32 g sample of neon gas exert a pressure of 398 torr in a 4.99 L container?

Answer 1

Ideal gas law: PV = nRT

P = pressure = 398 torr x 1 atm / 760 torr = 0.5237 atm

V = volume in liters = 4.99 L

n = moles = 3.32 g Ne x 1 mol Ne / 20.18 g = 0.1645 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in Kelvin = ?

Solve for T:

T = PV / nR

Plug in the values and solve