Nicholas O. answered 05/07/23
Highly Qualified High School Math Teacher for 7+ Years
a) The mean of the sampling distribution is equal to the mean of the sample µ = 4.47. The standard deviation of the sampling distribution is σx = σ⁄√n. So σx = 1.4 ⁄√100 = 1.4/10 = .14
b) The central limit theorem states that the sampling distribution of the mean will always be normally distributed as long as the sample size is large enough (usually n ≥ 30). So since the sample size of 100 is large, the sampling distribution will be approximately normal.