confidence interval

Question

A botanist wishes to estimate the typical number of seeds for a certain fruit. She samples 52 specimens and counts the number of seeds in each. Use her sample results (mean = 47.3, standard deviation = 5.2) to find the 80% confidence interval for the number of seeds for the species. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. 



Answer 1

CI = x̄ ± z(s/√n)

CI_80% = 47.3 ± 1.28(5.2/√52)

CI_80% ≈ (46.377,48.223)

Therefore, we are 80% confident that the true number of seeds for the species is contained within the interval (46.377,48.223).

Hope this helped!